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Carl Spence
Mathematics
22 May, 16:30
2 sin 2θ - 3 sin θ = 0
+2
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Addyson Lang
22 May, 16:37
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(-1/4)
...
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Wilkerson
22 May, 16:40
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Sin2θ = 2sinθcosθ
2 sin 2θ - 3 sin θ = 0
2 (2sinθcosθ) - 3 sin θ = 0
4sinθcosθ - 3sin θ = 0
sinθ (4cosθ - 3) = 0
sinθ = 0, 4cosθ - 3 = 0 cosθ = 3/4
θ = sin⁻¹ (0) θ = cos⁻¹ (0.75)
θ = 0, 180, 360 degrees, θ ≈ 41.41°, 360 - 41.41 = 318.59°
θ = 0°, 180°, 360°, ≈ 41.41°, ≈ 318.59°
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