17x^3+7x^2-4x-44 how do you solve this

Question

Judd

Mathematics

13 September, 03:04

17x^3+7x^2-4x-44 how do you solve this

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Clayton · Answer 1

17x^3 + 7x^2 - 4x - 44 = 0

17x^3 + 7x^2 - 4x = 44

x (17x^2 + 7x - 4) = 44

x = 44, or complete the square on the quadratic ...

17x^2 + 7x - 4+4 = 44+4

17x^2 + 7x = 48

(17x^2 + 7x) / 17 = 48/17

x^2 + 7/17x = 48/17

(x + 7/34) ^2 - (49/1156) = (48/17) - (49/1156)

(x + 7/34) ^2 - (49/1156) + (49/1156) = (48/17) • (68/68) + (49/1156)

(x + 7/34) ^2 = (48/17) • (68/68) + (49/1156)

(x + 7/34) ^2 = (3264/1156) + (49/1156)

(x + 7/34) ^2 = (3313/1156)

(x + 7/34) ^2 = 2.866

SR [ (x + 7/34) ^2] = SR (2.866)

(x + 7/34) = + / - 1.6929

(x +.2059) = + / - 1.6929

x +.2059 = + 1.6929, and x +.2059 = - 1.6929

x +.2059 = + 1.6929--> x = 1.6929-.2059 - - > x = 1.487

x +.2059 = - 1.6929--> x = - 1.6929 + -.2059 - - > x = - 1.899

So roots or solutions are:

x = 44, x = 1.487, & x = - 1.899