Ask Question
13 September, 03:04

17x^3+7x^2-4x-44 how do you solve this

+1
Answers (1)
  1. 13 September, 03:24
    0
    17x^3 + 7x^2 - 4x - 44 = 0

    17x^3 + 7x^2 - 4x = 44

    x (17x^2 + 7x - 4) = 44

    x = 44, or complete the square on the quadratic ...

    17x^2 + 7x - 4+4 = 44+4

    17x^2 + 7x = 48

    (17x^2 + 7x) / 17 = 48/17

    x^2 + 7/17x = 48/17

    (x + 7/34) ^2 - (49/1156) = (48/17) - (49/1156)

    (x + 7/34) ^2 - (49/1156) + (49/1156) = (48/17) • (68/68) + (49/1156)

    (x + 7/34) ^2 = (48/17) • (68/68) + (49/1156)

    (x + 7/34) ^2 = (3264/1156) + (49/1156)

    (x + 7/34) ^2 = (3313/1156)

    (x + 7/34) ^2 = 2.866

    SR [ (x + 7/34) ^2] = SR (2.866)

    (x + 7/34) = + / - 1.6929

    (x +.2059) = + / - 1.6929

    x +.2059 = + 1.6929, and x +.2059 = - 1.6929

    x +.2059 = + 1.6929--> x = 1.6929-.2059 - - > x = 1.487

    x +.2059 = - 1.6929--> x = - 1.6929 + -.2059 - - > x = - 1.899

    So roots or solutions are:

    x = 44, x = 1.487, & x = - 1.899
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “17x^3+7x^2-4x-44 how do you solve this ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers