Find the solution to the system of equations: x + 3y = 7 and 2x + 4y = 8 1. Isolate x in the first equation: 2. Substitute the value for x into the second equation: 3. Solve for y: 4. Substitute y into either original equation: 5. Write the solution as an ordered pair: x = 7 - 3y 2 (7 - 3y) + 4y = 8 14 - 6y + 4y = 8 14 - 2y = 8 - 2y = - 6 y = 3 x + 3 (3) = 7 (,)

Question

Ayden Roy

Mathematics

21 September, 18:38

Find the solution to the system of equations: x + 3y = 7 and 2x + 4y = 8 1. Isolate x in the first equation: 2. Substitute the value for x into the second equation: 3. Solve for y: 4. Substitute y into either original equation: 5. Write the solution as an ordered pair: x = 7 - 3y 2 (7 - 3y) + 4y = 8 14 - 6y + 4y = 8 14 - 2y = 8 - 2y = - 6 y = 3 x + 3 (3) = 7 (,)

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Miriam Hines · Answer 1

X + 3y = 7

x = - 3y + 7

2x + 4y = 8

2 (-3y + 7) + 4y = 8

-6y + 14 + 4y = 8

-2y = 8 - 14

-2y = - 6

y = - 6/-2

y = 3

x + 3y = 7

x + 3 (3) = 7

x + 9 = 7

x = 7 - 9

x = - 2

solution is (-2,3)