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How do you solve:

3 (a+2) = 2 (a-7) and 9 (t-1) = 6 (t+2) - t

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Answers (2)
  1. 21 June, 07:09
    0
    t=3

    Step-by-step explanation:

    Simplifying

    5 + - 1 (t + 3) = - 1 + 2 (t + - 3) Reorder the terms:

    5 + - 1 (3 + t) = - 1 + 2 (t + - 3)

    5 + (3 * - 1 + t * - 1) = - 1 + 2 (t + - 3)

    5 + (-3 + - 1t) = - 1 + 2 (t + - 3)

    Combine like terms: 5 + - 3 = 2

    2 + - 1t = - 1 + 2 (t + - 3)

    Reorder the terms:

    2 + - 1t = - 1 + 2 (-3 + t)

    2 + - 1t = - 1 + (-3 * 2 + t * 2)

    2 + - 1t = - 1 + (-6 + 2t)

    Combine like terms: - 1 + - 6 = - 7

    2 + - 1t = - 7 + 2t

    Solving

    2 + - 1t = - 7 + 2t

    Solving for variable 't'.

    Move all terms containing t to the left, all other terms to the right.

    Add '-2t' to each side of the equation.

    2 + - 1t + - 2t = - 7 + 2t + - 2t

    Combine like terms: - 1t + - 2t = - 3t

    2 + - 3t = - 7 + 2t + - 2t

    Combine like terms: 2t + - 2t = 0

    2 + - 3t = - 7 + 0

    2 + - 3t = - 7

    Add '-2' to each side of the equation.

    2 + - 2 + - 3t = - 7 + - 2

    Combine like terms: 2 + - 2 = 0

    0 + - 3t = - 7 + - 2

    -3t = - 7 + - 2

    Combine like terms: - 7 + - 2 = - 9

    -3t = - 9

    Divide each side by '-3'.

    t = 3

    Simplifying

    t = 3
  2. 21 June, 07:26
    0
    There are many many steps, but the answer is t=3
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