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6 February, 03:59

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

A rocket is launched from atop a 76-foot cliff with an initial velocity of 135 ft/s.

A.) Substitute the values into the vertical motion formula h=-16t^2+vt+c. Let h=0

B.) Use the quadratic formula find out how long the rocket will take to hit the ground after it is launched. Round to the nearest tenth of a second.

1.) 0 = - 16t^2 + 135t + 76; 0.5 s

2.) 0 = - 16t^2 + 135t + 76; 9 s

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Answers (1)
  1. 6 February, 04:27
    0
    A) h = - 16 t² + 135 t + 76

    Let : h = 0

    0 = - 16 t² + 135 t + 76

    B) t 1/2 = (-b + / - √ (b² - 4 ac) / (2 a)

    t 1/2 = (-135 - √ (18,225 + 4,864)) / (-32) = ( - 135 - 151.95) / ( - 32) =

    = (-286.95) / ( - 32) = 9.967 ≈ 9.0 s (other solution is negative)

    Answer:

    2) 0 = - 16 t² + 135 t + 76; 9 s
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