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28 August, 20:23

How many liters of 10% alcohol solution and 5% alcohol solution must be mixed to obtain 40 liters of 8%

alcohol solution?

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  1. 28 August, 20:42
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    x+y=40liters

    10%x+5%y=8%*40

    (2x+y) / 20=8%*40

    (2x+y) = 64

    x=24

    y=16
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