The rectangle shown has a perimeter of 78 cm and the given area. Its length is 3 more than five times its width. Write and solve a system of equations to find the dimensions of the rectangle.

So W is going to stand for width and L is going to stand for length.

L = 2W+6

78=2L + 2W

Those are the two equations you will use. So plug in L=2W+6 into the other one and solve.

78 = 4W+12 + 2W

(simplify)

78=6W+12

(-12 from both sides)

66=6W

(divide by 11)

W=11

Replug W into your equation to find L.

L=22+6

(simplify)

L=28

I hope this is right