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1 November, 20:16

Sally is given the information ƒ (1) = 0, ƒ (-2) = 0 and ƒ (3) = 0. which are the factors of the polynomial?

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  1. 1 November, 20:33
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    F (1) = 0 tells you that wherever you see an x, you put in a one. When you do, the answer comes out as 0

    So one of he factors for f (x) is

    f (x) = (x - 1) * g (x)

    If you put an 1 into (x - 1) you get (1 - 1) = 0

    The whole thing goes to zero when that happens.

    If you split up g (x) so that when x = - 2, the whole polynomial goes to 0 just as what happened with x = 1

    f (x) = (x - 1) (x + 2) * h (x)

    When x = 3 the same thing happens.

    f (x) = (x - 1) (x + 2) (x - 3) and that's your complete answer.
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