How do you transform the polar equation theta=pi/6 to an equation in rectangular coordinates and identify its shape?

You are given the theta function θ=π/6, suppose that you have a radius of 4, then we have a polar coordinate of (4,π/6). To change into rectangular form, this is also equal to

x = 4cosπ/6 and y = 4sinπ/6

x = 2√3 and y = 2

(2√3, 2)