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18 July, 22:57

How does the volume of a square pyramid change if the base area is quadrupled and the height is reduced to 1/9 of its original size

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  1. 18 July, 23:20
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    The volume of a square pyramid is solved through the equation,

    V = Bh/3

    where V is volume, B is the area of the base, and h is the height. When we substitute the new values to the equation,

    V = (4B) (h/9) / 3

    V = (4/9) (Bh/3)

    As seen in the equation above, the volume is multiplied by 4/9.
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