The area of a rectangle is 42 ft ^2 and the length of the rectangle is 5ft more than twice the width. Find the dimensions of the rectangle.

Length: Ft

Width: Ft

Question

Guest

Mathematics

25 March, 21:18

The area of a rectangle is 42 ft ^2 and the length of the rectangle is 5ft more than twice the width. Find the dimensions of the rectangle.

Length: Ft

Width: Ft

+3

Answers (1)

Know the Answer?

Kale Huff · Answer 1

Step-by-step explanation:

Width = x

Length = 2x+5

Area = length * breadth

42=x (2x+5)

42=2x^2+5x

0=2x^2+5x-42

Solve for X.

The positive value is the answer because the length cannot be a negative value.

Then substitute the x value to get the length and the breadth.

The area of a rectangle is 42 ft ^2 and the length of the rectangle is 5ft more than twice the width. Find the dimensions of the rectangle.Length: FtWidth: Ft

The area of a rectangle is 42 ft ^2 and the length of the rectangle is 5ft more than twice the width. Find the dimensions of the rectangle.

Length: Ft

Width: Ft