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15 October, 14:49

What is the smallest integer greater than 1 that leaves a remainder of 1 when divided by any of the integers 6,8 and 10?

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  1. 15 October, 15:18
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    It leaves a remainder of 3

    that means is it NOT a multipule of 6 or 8 or 10

    it has to be more than 10 though

    6x+1=8y+1=10z+1

    subtract 1 from everybody

    6x=8y=10z

    so basically what is the least common multplule and then add 1

    LCM

    factor

    6=2*3

    8=2*2*2

    10=2*5

    therefor the LCM=2*2*2*3*5=120

    then add 1

    120+1=121

    the smallest intege is 121
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