It p (x) = x2 - 1 and 0 (X) - 5 (x-1), which expression is equivalent to (0-2) (x) ?
5 (x - 1) - x2 - 1
(5x - 1) - (x2 - 1)
(x2 - 1) - 5 (x - 1)
(x2 - 1) - 5x - 1
+3
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