10 (2y+2) - y=2 (8y-8)

y = ?

10 (2y+2) - y=2 (8y-8)

20y + 20 - y = 16y - 16

19y - 16y = - 16 - 20

3y = - 36

y = - 36/3

y = - 12

Y = - 12

- distribute the 10 into (2y+2)

- distribute 2 into (8y-8)

You will have 20y + 20 - y = 16y - 16

- bring the 20 to the other side to get

20y - y = 16y - 36

- subtract y from 2y to get 19y = 16y - 36

- bring 16y to the other side to get 3y = - 36

- divide 3 from both sides to single out y.

Your final answer is y = - 12