What are the vertex and x-intercepts of the graph of the function below? y = (x + 4) (x - 2)

Y = (x + 4) (x - 2)

The x-intercepts:

0 = x + 4

0 = x - 2

x = - 4

x = 2

The vertex:

y = (x + 4) (x - 2)

y = x^2 + 2x - 8

x = - b/2a

If ax^2 + bx + c, then:

a = 1

b = 2

c - 8

x - 2/2 (1)

x = - 1

y = (-1) ^2 + 2 (-1) - 8

y = - 9

The vertex is (-1, - 9)

The x-intercepts are - 4 and 2