Ask Question
25 January, 21:58

A goblet contains 2 red marbles, 6 green marbles, and 4 blue marbles.

If we choose a marble, then another marble without putting the first one back in the goblet, what is the probability that the first marble will be green and the second will be green as well?

+2
Answers (2)
  1. 25 January, 22:06
    0
    The probability that the first marble will be green is 1/2 (0.5).

    The probability that the second marble will be green is 5/11 (0.45)

    We must multiply the two probabilities together to find the probability of both occurring.

    This equals 0.227 (11/50).
  2. 25 January, 22:10
    0
    The probability is (6/12) * (5/11) = 5/22
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A goblet contains 2 red marbles, 6 green marbles, and 4 blue marbles. If we choose a marble, then another marble without putting the first ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers