Find the center and radius of the circle whose equation is x 2 + y 2 - 6x - 2y + 4 = 0

A = 1

b = - 6

c = (y^2 - 2y + 4)

x^2 - 6x + 9 - 9 + y^2 - 2y + 4

(x - 3) ^2 - 9 + y^2 - 2y + 4

(x - 3) ^2 - 5 + y^2 = 2y = 0

(x - 3) ^2 + y^2 - 2y = 5

(x - 3) ^2 - 2y = 5 - y^2

(x - 3) ^2 = 5 - y^2 + 2y

(x - 3) ^2 = 5 - y^2 + 2y

x - 3 = ¥√5 - y^2 + 2y

x = √5 - y^2 + 2y + 3, - √5 - y^2 + 2y + 3