The gym offers a discount when more than one member of the family joins. The first member (n=10) pays $550 per year. The second member to join (n=1) get discount of $75 per yar. The third member (n=2) gets an additional $75. The price for the nth member is given by 550 + (-75n)

a. What is the price for the fourth member to join (n=3)

b. For a large family, is it possible for a member to would join free? If so, which member would it be? Explain you reasoning

c. Other than $0, what is the lowest amount that member would pay to join? Which member would it be? Explain your reasoning

Question

Edward Kemp

Mathematics

6 December, 20:17

The gym offers a discount when more than one member of the family joins. The first member (n=10) pays $550 per year. The second member to join (n=1) get discount of $75 per yar. The third member (n=2) gets an additional $75. The price for the nth member is given by 550 + (-75n)

a. What is the price for the fourth member to join (n=3)

b. For a large family, is it possible for a member to would join free? If so, which member would it be? Explain you reasoning

c. Other than $0, what is the lowest amount that member would pay to join? Which member would it be? Explain your reasoning

+4

Answers (1)

Know the Answer?

Landry · Answer 1

A. 550 - (3x75) = 325

b. The 9th member may join free as 550 - (75x8) = - 50 and as I imagine the gym will not pay the customer money they should have a free membership but only after the 9th person.

c. $25, 550 - (75x7) = 25 therefore the 8th person pays $25 for their membership.