Given the cos theta is 12/13 and that the angle theta terminates in quadrant 4 l, then what is the value of sin theta

5/13

Step-by-step explanation:

R^2 = x^2 + y^2

x is cosine

y is sine

r is the value in the denominator (here it is 13)

Plug it in:

13^2 = 12^2 + y^2

169 = 144 + y^2

Subtract 144 from both sides:

169 - 144 = y^2

25 = y^2

Square root both sides:

y = 5

in other words, sin theta = 5/13