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Let f (x) = (6x^3-7) ^3 and g (x) = 6x^3-7 Given that f (x) = (h*g) (x), find h (x).

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  1. 13 July, 02:39
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    F (x) = (6x^3 - 7) ^3 = h (x) * (6x^3-7)

    h (x) = (6x^3-y) ^3 / (6x^3-7) = (6x^3 - 7) ^2
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