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13 December, 23:00

How many solutions are there to this system? A. None B. Exactly 1 C. Exactly 2 D. Exactly 3 E. Infinitely many F. None of the above

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  1. 13 December, 23:03
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    Hello, you haven't provided the system of equations, therefore I will show you how to do it for a particular system and you can follow the same procedure for yours.

    Answer:

    For E1 - > Exactly one

    For E2 - > None

    For E3 - > Infinitely many

    Step-by-step explanation:

    Consider the system of equations E1: y = - 6x + 8 and 3x + y = 4, replacing equation one in two 3x - 6x + 8 = 4, solving x = 4/3 and replacing x in equation one y = 0. This system of equations have just one solution - > (4/3, 0)

    Consider the system of equations E2: y = - 3x + 9 and y = - 3x - 7, replacing equation one in two - 3x + 9 = - 3x - 7, solving 9 = - 3. This system of equations have no solution because the result is a fallacy.

    Consider the system of equations E3: 2 = - 6x + 4y and - 1 = - 3x - 2y, taking equation one and solving y = 1/2 + 3/2x, replacing equation one in two - 1 = - 3x - 1 + 3x, solving - 1 = - 1. This system of equations have infinitely many solution because we find a true equation when solving.
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