X2 + 2x + 5 = 0 solve with quadratic formula

x = - 1 ± 2i

Step-by-step explanation:

The standard form of a quadratic equation is ax² + bx + c = 0, and the quadratic formula is x = [-b ± √ (b ² - 4ac) ] / 2a

In this case, a = 1, b = 2 and c = 5. Now you have to substitute in the quadratic formula:

x = [-b ± √ (b ² - 4ac) ] / 2a

x = [-2 ± √ (2 ² - 4*1*5) ] / 2*1

x = [-2 ± √ (4 - 20) ] / 2

x = [-2 ± √ (-16) ] / 2

Since the square root is negative, you have to use imaginary numbers to continue solving the equation. Remmber that √ (-1) = i.

x = [-2 ± √ (-16) ] / 2

x = [-2 ± √ (16) i ] / 2

x = [-2 ± 4i ] / 2

x1 = [-2 + 4i ] / 2

x1 = - 1 + 2i

x2 = [-2 - 4i ] / 2

x2 = - 1 - 2i

So the answers of x are - 1 ± 2i