Ask Question
10 September, 16:29

An aquifer holds 146,000 cubic feet of water. Water exits through a well at a steady rate of 500 cubic feet per day, and the aquifer is replenished at a constant rate of x cubic feet per day. If the water in the aquifer is used up in a year (365 days), what is the value of x? Ignore evaporation and other losses.

+4
Answers (1)
  1. 10 September, 16:32
    0
    The value of x = 100 ft^3 / day

    Step-by-step explanation:

    We need to look at what amount of water comes in and what amount of water leaves

    What comes in: x ft^3 / day

    What leaves : 500x ft^3 / day

    We start with 146 000 ft^3

    Water in tank = what we start with + what comes in - what leaves

    water in tank = 146000 + x*d - 500*d where d is the number of days

    After 365 days, the tank has 0 ft^3 of water

    0 = 146000 + x*365 - 500*365

    Multiply

    0 = 146000 + 365x - 182500

    Combine like terms

    0 = - 36500+365x

    Add 36500 to each side

    36500 = 36500-36500+365x

    36500 = 365x

    Divide by 365

    36500/365 = 365x/365

    100=x

    The value of x = 100
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “An aquifer holds 146,000 cubic feet of water. Water exits through a well at a steady rate of 500 cubic feet per day, and the aquifer is ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers