You flip a fair coin 10,000 times. Approximate the probability thatthe difference between the number of heads and the number of tails is at most 100.

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Creep

Mathematics

28 July, 05:06

You flip a fair coin 10,000 times. Approximate the probability thatthe difference between the number of heads and the number of tails is at most 100.

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Walter Calderon · Answer 1

E[X] = (np) (p + (1-p)) ^ (n-1)

With n = 10,000 and p=0.50 we get

E[X] = (10,000*0.50) (0.50 + (1-0.50)) ^ (10,000-1)

E[X] = 5,000 (1)

So assuming the coin is fair (p=50%), then we can expect to get heads 5,000 times when the coin is tossed 10,000 times.