In a rectangle the length is 6 more than twice the width, if the perimeter is 60 inches, what is the width of the rectangle

Length (l) = 2w+6

width (w) = w

Perimeter (P) = 60 inches = 2w+2l (divide each side by 2 to simplify)

P=30 in = w+l

Plug in expression for "l" to be able to add like terms.

P=30=w+l

P=30=w + (2w+6)

P = 30 = 3w+6

P = 24 = 3w

w = 8 inches

Answer:

The width of the rectangle is 8 inches.