Write (9+6/) - (1+3/) as a complex number in a standard form

(9 + 6i) - (1 + 3i) as a complex number in standard form is 8 + 3i

Solution:

Given that we have to write (9 + 6i) - (1 + 3i) as a complex number in standard form

A Complex Number is a combination of real Number and an imaginary Number

The standard form of complex number is:

a + bi

Where "a" and "b" are real numbers and i is the unit imaginary number

Given expression is:

(9 + 6i) - (1 + 3i)

Remove the parenthesis and solve the expression

9 + 6i - 1 - 3i

Combine the like terms

9 + 6i - 1 - 3i = 8 + 3i

Thus the given expression as complex number in standard form is 8 + 3i