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9 September, 00:18

Find two consecutive integers such that twice the larger is the same as two less than three times the smaller.

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  1. 9 September, 00:31
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    Ans = > 4, 5

    Step-by-step explanation:

    let the integers be x and y

    if they are consecutive, that means the larger integer is one greater than the smaller

    => y = x+1

    2 = 3x - 2y

    3x - 2 (x+1) = 2

    3x - 2x - 2 = 2

    x = 4

    y = 4+1 = 5
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