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4 October, 00:53

The longest side of an obtuse triangle measures 20 cm. The two shorter sides measure x cm and 3x cm.

Rounded to the nearest tenth, what is the greatest possible value of x?

6.3

6.4

7.0

7.1

+3
Answers (1)
  1. 4 October, 01:17
    0
    If an obtuse triangle is given and 20 cm is the longest side, then:

    x² + (3x) ² < 20²

    x² + 9x² < 400

    10x² < 400

    x² < 40

    x < 6.3

    So, the greatest possible value of x could be 6.29999 ... ≈ 6.3 to the nearest tenth.
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