Eli has 7 black pens and 6 blue pens in his desk drawer. he also has 4 yellow highlighters, 2 green highlighters, and 3 pink highlighters in his pencil case. if he chooses one pen and one highlighter without looking, what is the probability that he will get a blue pen and he will not get a pink highlighter?

Question

Yasmine Estes

Mathematics

31 August, 10:04

Eli has 7 black pens and 6 blue pens in his desk drawer. he also has 4 yellow highlighters, 2 green highlighters, and 3 pink highlighters in his pencil case. if he chooses one pen and one highlighter without looking, what is the probability that he will get a blue pen and he will not get a pink highlighter?

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Answers (1)

Know the Answer?

Armani Chang · Answer 1

Probability that Eli will get a blue pen: 6 / 13 (there are 6 blue pens and 13 pens together).

Probability that Eli will not get the pink highlighter: 6 / 9 (yellow + green = 4 + 2 = 6 and there are 9 together).

P = 6/13 · 6/9 = 6/13 · 2/3 = 2/13 · 2 = 4/13 = 0.3077 = 30.77%.

Answer:

The probability is 4/13 or 30.77%.