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16 February, 05:43

An observation deck extends 314 feet out above a valley. The deck sits 264 feet above the valley floor. If an object is dropped from the observation deck, its height h in feet, after t seconds, is given by h equals negative 16 t squared plus 264. How long will it take for the object to be 8 feet above the valley floor?

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  1. 16 February, 06:11
    0
    4.12 s

    Step-by-step explanation:

    The equation given in the question that relates the height (h), and the time (t) is:

    h = - 16t² + 264

    So, for h = 8 ft

    8 = - 16t² + 264

    16t² = 264 + 8

    16t² = 272

    t² = 17

    t = √17

    Which can be approximadelly to 4.12 s
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