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27 September, 21:48

What are the solutions of the equation x4 - 9x2 + 8 = 0? Use u substitution to solve. x = 1 and x = 2 StartRoot 2 EndRoot x = ±1 and x = plus-or-minus 2 StartRoot 2 EndRoot x = ±i and x = plus-or-minus 2 i StartRoot 2 EndRoot x = ±i and x = 2 StartRoot 2 EndRoot

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  1. 27 September, 21:59
    0
    The solutions are

    x = - 1, 1, - 2√2, and 2√2.

    Step-by-step explanation:

    Given the equation

    x^4 - 9x² + 8 = 0

    Let u = x², then the equation becomes

    u² - 9u + 8 = 0

    u² - u - 8u + 8 = 0

    (u² - u) - (8u - 8u) = 0

    u (u - 1) - 8 (u - 1) = 0

    (u - 8) (u - 1) = 0

    u - 8 = 0

    => u = 8

    Or

    u - 1 = 0

    => u = 1

    For u = 8

    => x² = 8

    => x = ±√8 = ±2√2

    For u = 1

    => x² = 1

    => x = ±√1 = ± 1
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