Worker Efficiency An efficiency study conducted for Elektra Electronics showed that the number of Space Commander walkie-talkies assembled by the average worker during the morning shift t hr after starting work at 8 a. m. is given by

N (t) = - t3 + 6t2 + 15t (0 ≤ t ≤ 4).

(a) Find the rate at which the average worker will be assembling walkie-talkies t hr after starting work.

(b) At what rate will the average worker be assembling walkie-talkies, per hour, at 9 a. m.? walkie-talkies/hour At what rate will the average worker be assembling walkie-talkies, per hour, at 10 a. m.?

(c) How many walkie-talkies will the average worker assemble between 9 a. m. and 10 a. m.? walkie-talkies

Question

Sebastian Huang

Mathematics

27 April, 03:11

Worker Efficiency An efficiency study conducted for Elektra Electronics showed that the number of Space Commander walkie-talkies assembled by the average worker during the morning shift t hr after starting work at 8 a. m. is given by

N (t) = - t3 + 6t2 + 15t (0 ≤ t ≤ 4).

(a) Find the rate at which the average worker will be assembling walkie-talkies t hr after starting work.

(b) At what rate will the average worker be assembling walkie-talkies, per hour, at 9 a. m.? walkie-talkies/hour At what rate will the average worker be assembling walkie-talkies, per hour, at 10 a. m.?

(c) How many walkie-talkies will the average worker assemble between 9 a. m. and 10 a. m.? walkie-talkies

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Answers (1)

Know the Answer?

Gia Dalton · Answer 1

a) - 2t²+12t+15 b) 25, 31 c) 26

Step-by-step explanation:

a) To find out rate, we will take derivative of the given equation

dN/dt = - 2t2+12t+15

b) At 9 am, it will be 1hr since the start of morning shift so t=1

dN/dt = - 2 (1) ²+12 (1) + 15

dN/dt=25

At 10 am, it will 2 hrs since the start of morining shift be so t=2

dN/dt=-2 (2) ²+12 (2) + 15

DN/dt = 31

c) N (2) - N (1) = ( - (2) ³+6 (2) ²+15 (2)) - ( - (1) ³+6 (1) ²+15 (1))

= (46) - (20))

= 26