A box has 8 beads of the same size, but all are different colors. Tamy draws a bead randomly from the box, notes its color, and then puts the bead back in the box. She repeats this 3 times. What is the probability that Tamy would pick a red bead on the first draw, then a white bead, and finally a red bead again?

1 over 4096

1 over 512

1 over 64

1 over 8

Question

Dalton Villarreal

Mathematics

25 April, 03:45

A box has 8 beads of the same size, but all are different colors. Tamy draws a bead randomly from the box, notes its color, and then puts the bead back in the box. She repeats this 3 times. What is the probability that Tamy would pick a red bead on the first draw, then a white bead, and finally a red bead again?

1 over 4096

1 over 512

1 over 64

1 over 8

+4

Answers (1)

Know the Answer?

Anthony Leblanc · Answer 1

The probability of a red bead on the first draw is 1/8.

The probability of a white bead on the second draw is 1/8.

The probability of a red bead on the third draw is 1/8.

The probability of all three events is (1/8 x 1/8 x 1/8) = 1/512 = 0.001953125