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11 December, 00:54

X^2· (x+9) · (x-5) ≥0

what are all values of x

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  1. 11 December, 01:10
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    Step-by-step explanation:

    x² ≥0 for all real values.

    so we are concerned with (x+9) (x-5) ≥0

    x+9=0, x=-9

    x-5=0, x=5

    solution is values of x does not lie in these values.

    so x≤-9 or x≥5
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