A triangle has a perimeter of 33cm. If the three sides of the triangle are n, 3n-4 3n-4, and 3n-5 3n-5, what is the length of each side?

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Mathematics

28 November, 06:30

A triangle has a perimeter of 33cm. If the three sides of the triangle are n, 3n-4 3n-4, and 3n-5 3n-5, what is the length of each side?

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Answers (2)

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Barclay · Answer 1

The perimeter is the sum of the sides.

n + (3n - 4) + (3n - 5) = 33

7n - 9 = 33

7n = 42

n = 6

3n-4=18-4=14

3n-5=13

Check: 6+14+13=33, good

Answer: 6 cm, 14 cm, 13 cm

Porter Ray · Answer 2

6, 14, 13

Step-by-step explanation:

n + 3n - 4 + 3n - 5 = 33

7n - 9 = 33

7n = 33 + 9

7n = 42

n = 6

So, 3n - 4 = 14, 3n - 5 = 13