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28 November, 06:30

A triangle has a perimeter of 33cm. If the three sides of the triangle are n, 3n-4 3n-4, and 3n-5 3n-5, what is the length of each side?

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  1. 28 November, 06:38
    0
    The perimeter is the sum of the sides.

    n + (3n - 4) + (3n - 5) = 33

    7n - 9 = 33

    7n = 42

    n = 6

    3n-4=18-4=14

    3n-5=13

    Check: 6+14+13=33, good

    Answer: 6 cm, 14 cm, 13 cm
  2. 28 November, 06:49
    0
    6, 14, 13

    Step-by-step explanation:

    n + 3n - 4 + 3n - 5 = 33

    7n - 9 = 33

    7n = 33 + 9

    7n = 42

    n = 6

    So, 3n - 4 = 14, 3n - 5 = 13
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