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20 January, 10:54

Solve triangle ABC given that A=56 B=57 b=9

a) C=64, a=10.2, c=9.8

b) C=67, a=10.2, c=9.88

c) C=67, a=8.9, c=9.88

d) C=66, a=8.7, c=9.88

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Answers (2)
  1. 20 January, 11:08
    0
    Sin A/a = Sin B/b

    Sin 56/a = Sin 57/9

    a = (Sin 56/Sin 57) x 9

    a = 8.9

    c) C=67, a=8.9, c=9.88
  2. 20 January, 11:09
    0
    Sin A / a = sin B / b

    sin 56 / a = sin 57 / 9

    a = 9sin 56 / sin 57 = 8.9

    C = 180 - 56 - 57 = 67

    sin 67 / c = sin 57 / 9

    c = 9sin 67 / sin 57 = 9.88

    option c is the correct answer.
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