A candy store makes a 9 lbs. mixture of Reese's pieces, M&M's, and Hershey's Kisses. Reese's cost $2.80 per pound, M&M's cost $2.50, and Hershey's Kisses cost $1.20 per pound. The mixture calls for four pounds more Reese's pieces than M&M's. The total cost of the mixture is $23.00. How much of each ingredient did the store use? write the system of equations to solve this problem

Question

Bauer

Mathematics

4 July, 15:28

A candy store makes a 9 lbs. mixture of Reese's pieces, M&M's, and Hershey's Kisses. Reese's cost $2.80 per pound, M&M's cost $2.50, and Hershey's Kisses cost $1.20 per pound. The mixture calls for four pounds more Reese's pieces than M&M's. The total cost of the mixture is $23.00. How much of each ingredient did the store use? write the system of equations to solve this problem

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Answers (1)

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Micheal Lindsey · Answer 1

r+m+h = 9 r-m = 4 2.80r + 2.50m + 1.20h = 23.00

Step-by-step explanation:

Let r, m, h represent the numbers of pounds of Reese's Pieces, M&Ms, and Hershey's Kisses, respectively. The equations shown above represent the relationships described in the problem statement.

The first equation says the total amount of candy is 9 pounds.

The second equation says there are four more pounds of Reese's than of M&Ms.

The third equation says the total cost of the mix is $23.

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The solution can be found by various means to be ...

the mix consists of

6 pounds of Reese's Pieces 2 pounds of M&Ms 1 pound of Hershey's Kisses