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20 December, 16:36

Ned walks 6/10 of a mile to school. Fred walks 9/15 of a mile to school. Who walks farther?

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Answers (2)
  1. 20 December, 16:55
    0
    There are a few ways to solve the problem. I will use 2 ways. You can use equivalent fractions.

    Way 1:

    You find the LCM of 10 and 15.

    10: 10,20,30,40,50

    15: 15,30,45,60,75

    LCM of 10 and 15: 30

    30/10=3

    6*3=18

    6/10=18/30

    30/15=2

    9*2=18

    9/15=18/30

    18/30=18/30

    Since 6/10=9/15, Ned and Fred walked the same miles to school.

    Way 2:

    You could simplify 6/10 into 3/5 and simplify 9/15 into 3/5 by using GCF and since 3/5=3/5, 6/10=9/15. Since 6/10=9/15, Ned and Fred walked the same miles to school.
  2. 20 December, 16:57
    0
    6/10 of a mile would be 3168 feet. 9/15 of a mile would be 3168 feet as well. So therefore, they walked the same distance
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