Juan starts walking at 4 miles per hour. An hour and a half later, Cathy starts jogging along the same route at 7 miles per hour. How long will it take Cathy to catch up with Juan?

Answer: it take Cathy 3.75 to catch up with Juan

Step-by-step explanation:

Let t represent the time it will take for Cathy to catch up with Juan. At time t hours when Cathy will catch up Juan, they would have covered the same distance.

Juan starts walking at 4 miles per hour.

Distance = speed *, time

This means that the distance that Juan covered in to hours would be

4 * t = 4t

An hour and a half later, Cathy starts jogging along the same route at 7 miles per hour. Total time spent by Cathy would be t - 1.5

Distance covered by Cathy would be

7 (t - 1.5) = 7t - 10.5

Since the distance covered is the sane, the.

4t = 7t - 10.5

7t - 4t = 10.5

3t = 10.5

t = 10.5/3 = 3.5 hours

The answer to your question is 2 hours

Step-by-step explanation:

Data

Juan speed = 4 mi/h

Cathy speed = 7 mi/h

t = x

Formula

speed = distance/time

Solve for distance

distance = speed x time

d = s x t

Distance travelled by Juan

d = 4t

Distance travelled by Juan in 1.5 h

d = 4 (1.5)

d = 6 mi

total distance d = 6 + 4t

Distance travelled by Cathy

d = vt

d = 7t

Equal both equations

6 + 4t = 7t

Solve for t

6 = 7t - 4t

6 = 3t

6/3 = t

2 = t

Cathy wll catch up with Juan in 2 hours