4 women must cross a bridge over a deep ravine in enemy territory in the middle of the night. The bridge will only old two women at once and it is necessary to carry a lantern while crossing. One of the women requires 25 minutes, one 20 minutes, one 10 minutes and one 5 minutes. Each of them can walk slower but not faster. Unfortunately they have only one lantern among them. How can they make the crossing if they have only 60 minutes before the bridge is destroyed?

Question

Kameron Lewis

Mathematics

29 April, 04:08

4 women must cross a bridge over a deep ravine in enemy territory in the middle of the night. The bridge will only old two women at once and it is necessary to carry a lantern while crossing. One of the women requires 25 minutes, one 20 minutes, one 10 minutes and one 5 minutes. Each of them can walk slower but not faster. Unfortunately they have only one lantern among them. How can they make the crossing if they have only 60 minutes before the bridge is destroyed?

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Kelsie Andersen · Answer 1

First the 5 and 10 minute people cross, then the 5 minute person goes back with lantern (so 15minutes is used) and you have 5,20 and 25 still to cross then the 20 and 25 minute goes across (which means 25 + 15 = 40mins is used) then 10mintue person (which has already crossed), goes back to the start with the lantern (which means 40+10 = 50mintues used). then the 5 and 10mintue cross (10+50 = 60mintues) and all have crossed.