Square root 4x divided by 2x+1 = 3 solve

sqrt (4x) / 2x + 1 = 3

Set domain:

2x + 1 cannot equal 3

2x cannot equal 2 | : 2

x cannot equal 1

sqrt (4x) = 3 (2x + 1)

sqrt (4x) = 6x + 3

4x = 36x^2 + 9

36x^2 - 4x + 9 / f (x) = ax^2 + bx + c

16-4*36*9

16-1296 = - 1280

There's no solutions in Real Number set.