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13 July, 01:21

A student factored 6 x^9y^2 + 2xy as 2xy (3x^8y) What went wrong? Factor correctly.

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  1. 13 July, 01:41
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    In the problem that the student factored incorrectly, they left out a term. Even though you factored out 2xy, you still need to leave a 1 in its place, so you can distribute it back out. If you distribute out the incorrectly factored equation, you will get 6x^9y^2. If you distribute out 2xy (3x^8y+1), you will get 6x^9y^2+2xy.
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