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7 October, 16:56

Solve these systems of equations Using the elimination method.

a). 3x + y = 13 b) 6x - y = 14

x - 5y = 15 2x + y = 12

c) 3x - 4y = 22

2x + 5y = 7

+1
Answers (2)
  1. 7 October, 17:01
    0
    A). 3x + y = 13

    x - 5y = 15

    multiplier equation 1 by 5

    15x+5y=65

    DSA

    15x+5y=65

    x - 5y = 15

    remaini ng

    16x=80

    x=5

    5-5y=15

    -5y=15-5

    -5y=10

    y = 10 : - 5

    y=-2

    x, y

    5,-2
  2. 7 October, 17:04
    0
    A. 3x + y = 13 → 15x + 5y = 65

    x - 5y = 15 → x - 5y = 15

    16x = 80

    16 16

    x = 5

    x - 5y = 15

    5 - 5y = 15

    - 5 - 5

    -5y = 10

    -5 - 5

    y = - 2

    (x, y) = (5, - 2)

    b. 6x - y = 14

    2x + y = 12

    8x = 26

    8 8

    x = 3¹/₄

    6x - y = 14

    6 (3¹/₄) - y = 14

    19¹/₂ - y = 14

    - 19¹/₂ - 19¹/₂

    -y = - 5¹/₂

    -1 - 1

    y = 5¹/₂

    (x, y) = (3¹/₄, 5¹/₂)

    c. 3x - 4y = 22 → 15x - 20y = 110

    2x + 5y = 7 → 8x + 20y = 28

    23x = 138

    23 23

    x = 6

    3x - 4y = 22

    3 (6) - 4y = 22

    18 - 4y = 22

    - 18 - 18

    -4y = 4

    -4 - 4

    y = - 1

    (x, y) = (6, - 1)
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