The function E (d) = 0.25d√ approximates the number of seconds it takes a dropped object to fall d feet on Earth. The function S (d) = 0.2⋅E (d) approximates the number of seconds it takes a dropped object to fall d feet on the sun. How long (in seconds) does it take a dropped object to fall 80 feet on the sun? Round your answer to the nearest hundredth.

0.45 second

Step-by-step explanation:

The number of seconds it takes a dropped object to fall d feet on Earth is given as:

E (d) = 0.25√d

the number of seconds it takes a dropped object to fall d feet on the sun is given as:

S (d) = 0.2⋅E (d)

Therefore

S (d) = 0.2 * 0.25√d = 0.05√d

Given that it take a dropped object to fall 80 feet on the sun (i. e d = 80 feet), to calculate the time in seconds we use:

S (d) = 0.05√d

S (d) = 0.05 * √80 = 0.05 * 8.944 ≈ 0.45 s

It takes 0.45 second for a dropped object to fall 80 feet on the sun