Store 1 earned 10% of the money invested I it while store 2 lost 8% of the amount invested in it. The net total gain was $1,300. This year the respective quantities were + 6%, + %5 and $2,250. Find the merchants investment for each store

Question

Ruby Gillespie

Mathematics

17 April, 09:51

Store 1 earned 10% of the money invested I it while store 2 lost 8% of the amount invested in it. The net total gain was $1,300. This year the respective quantities were + 6%, + %5 and $2,250. Find the merchants investment for each store

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Answers (1)

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Dennis Dougherty · Answer 1

Store 1 = $150

Store 2 = $250

Step-by-step explanation:

Let the amount invested by store 1 be x while store 2 be y hence

10x-8y=1300 Eqn 1

Make x the subject of the formula for the first equation

10x=1300+8y divide both sides by 10

X=130+0.8y

6x+5y=2250 Eqn 2

Substituting where there's x with 130+0.8y in equation 2 we obtain

6 (130+0.8y) + 5y=2250

780+4.8y+5y=2250

9.8y+780=2250

9.28y=2250-780=1470

Y=1470/9.8=150

X=130+0.8y = 130+0.8 (150) = 250