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28 July, 13:07

1+3/x+1=x/x-1 state the excluded value, solve, state the solution set

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  1. 28 July, 13:09
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    1 + 3/x + 1 = x/x - 1

    4/x + 1 = x/x - 1

    4 (x - 1) = x (x + 1)

    4 (x) - 4 (1) = x (x) + x (1)

    4x - 4 = x² + x

    - x - x

    3x - 4 = x²

    3x = 4 + x²

    3 3

    x = 1.33 + 0.33x²
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