Im stuck on a algebra 2 question

f (x) = - 2x + 8 and g (x) = 3x^2 - 1

find f (f (-2))

f (f (-2) = - 16

Step-by-step explanation:

The first step is to evaluate the function f at - 2

f (-2) = - 2 (-2) + 8

f (-2) = 4+8

=12

Then we evaluate the function f at x=12

f (12) = - 2 (12) + 8

= - 24 + 8

= - 16

f (f (-2) = - 16

f (f ( - 2)) = - 16

Step-by-step explanation:

To evaluate f (f ( - 2)), evaluate f ( - 2) then evaluate f (x) for this value

f ( - 2) = ( - 2 * - 2) + 8 = 4 + 8 = 12, hence

f (12) = ( - 2 * 12) + 8 = - 24 + 8 = - 16