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13 July, 08:58

A hyperbola centered at the origin has vertices at (0,±/sqrt (54) and foci at (0,±/sqrt (89)

Write the equation of this hyperbola

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  1. 13 July, 09:06
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    answer:The equation has the form y2a2-x2b2=1 y 2 a 2 - x 2 b 2 = 1, so the transverse axis lies on the y-axis. The hyperbola is centered at the origin, so the vertices serve as the y-intercepts of the graph. To find the vertices, set x=0 x = 0, and solve for y y.
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