A menu offers a choice of 2 salads, 6 main dishes, and 5 desserts. How many different meals consisting of one salad, one main dish, and one dessert are possible?

60 different meals

Step-by-step explanation:

The possibilities of 1 salad = 2

The possibilities of 1 main dishes = 6

The possibilities of 1 desert = 5

Then we multiply all the types of posibilities together in other to have different meals consisting of one salad, one main dish, and one dessert

2*5*6 = 60

Cheers

Answer is 60

Step-by-step explanation:

The possibility of a salad meal is = 2

2C1 = 2

The possibility of a main dish = 6

6C1 = 6

The possibility of a dessert is = 5

5C1 = 5

So the total possibility is the multiplication of the three i. e

2*6*5 = 60

The principle applied is the combination principle.

Note that C stands for combination