Ask Question
2 October, 23:55

6x + 1 = 2 (3x - 2) + 5 A) x = 0 B) x = 12 C) x = 1 12 D) infinitely many solutions

+5
Answers (2)
  1. 3 October, 00:04
    0
    D) infinitely many solutions

    Step-by-step explanation:

    6x + 1 = 2 (3x - 2) + 5

    Distribute

    6x+1 = 6x - 4+5

    Combine like terms

    6x+1 = 6x+1

    Subtract 6x from each side

    6x-6x+1 = 6x-6x+1

    1=1

    This is always true, so x has infinite solutions
  2. 3 October, 00:11
    0
    6x + 1 = 2 (3x - 2) + 5

    6x + 1 = 6x - 4 + 5

    6x + 1 = 6x + 1

    6x = 6x

    x = x

    D.) Infinitely many solutions
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “6x + 1 = 2 (3x - 2) + 5 A) x = 0 B) x = 12 C) x = 1 12 D) infinitely many solutions ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers